Answer
See graph and explanations.
Work Step by Step
Step 1. Rearrange the equation to get $y^-12y+36=-6x+36+30$ or $(y-6)^2=-6(x-11)$ which indicates a parabola centered at $(11, 6)$.
Step 2. Graph the equation as shown in the figure.
Step 3. We can identify the equation as a parabola from the graph.
