Answer
See graph and explanations.
Work Step by Step
Step 1. Divide 36 on both sides of the equation to get $\frac{x^2}{4}-\frac{y^2}{3}+1=0$ or $\frac{y^2}{3}-\frac{x^2}{4}=1$ which indicates a hyperbola with $a=\sqrt 3, b=2$.
Step 2. Graph the equation as shown in the figure.
Step 3. We can identify the equation as a hyperbola from the graph.