Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 755: 47

Answer

$20, 15$

Work Step by Step

Step 1. Assume the length is $x$ and the width is $y$. Step 2. Based on the given conditions, set up the system of equations: \begin{cases} 2(x+y)=70 \\ x^2+y^2=25^2\end{cases} Step 3. The first equation gives: $y=35-x$, use it in the second equation to get: $x^2+(35-x)^2=25^2$ or $2x^2-70x+35^2-25^2=0$ or $x^2-35x+300=0$ Step 4. Factor the above equation as $(x-20)(x-15)=0$ to get $x=15, 20$ Step 5. Consider $x$ is the length, we can get the answer as $x=20, y=15$
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