Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 755: 45

Answer

12cm by 15cm.

Work Step by Step

Step 1. Assume the sides of the rectangle are $x$ cm and $y$ cm, with the given conditions, we can set up the following system of equations: \begin{cases} xy=180 \\ 2(x+y)=54 \end{cases} Step 2. From the first equation, we get $y=\frac{180}{x}$, substitute it in the second equation to get: $2(x+\frac{180}{x})=54$ or $x^2-27x+180=0$ Step 3. Solve the above quadratic equation with factoring or a formula: $(x-12)(x-15)=0$ and we get $x=12cm or 15cm$ Step 4. Back-substitute the results into the first equation, we get $x=12cm, y=15cm$ or $x=15cm, y=12cm$ Step 5. We conclude that the sizes of the rectangle are 12cm by 15cm.
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