Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.8 - Systems of Nonlinear Equations - 10.8 Exercises - Page 755: 46

Answer

7 ft and 24 ft.

Work Step by Step

Step 1. Assume the lengths of the other two sides are $x$ ft and $y$ ft. Step 2. Use the Pythagorean's Theorem, we have $x^2+y^2=25^2=625$ Step 3. The area of the triangle can be represented as $\frac{1}{2}xy=84$ Step 4. Thus, we have the following system of equations: \begin{cases} x^2+y^2=625 \\ xy=168 \end{cases} Step 5. The second equation gives $y=\frac{168}{x}$, use it to substitute the variable in the first equation, we have: $x^2+(\frac{168}{x})^2=625$ Step 6. Multiply $x^2$ on both sides, we have $x^4-625x^2+168^2=0$ Step 7. We can solve the above equation by letting $z=x^2$ and use a quadratic formula, however, we can just graph the function as shown and find the solutions as $x=7, 24$ ft. Step 8. Back-substitute $x$-values into the second equation to get $y=24, 7$ft. Step 9. We conclude the lengths of the other sides as 7 ft and 24 ft.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.