Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.6 - Determinants and Cramer's Rule - 10.6 Exercises - Page 744: 67

Answer

See explanations.

Work Step by Step

Step 1. Start from the original, do the operations: $R_1-R_2\to R_1$ and $R_2-R_3\to R_2$ $\begin{array}( \\|A|= \\ \\ \end{array} \begin{vmatrix} 0&x-y&x^2-y^2\\0&y-z&y^2-z^2\\1&z&z^2 \end{vmatrix}$ Step 2. Use the last row for expansion: $\begin{array}( \\|A|= \\ \\ \end{array} \begin{vmatrix} x-y&x^2-y^2\\y-z&y^2-z^2\end{vmatrix}$ Step 3. Complete the expansion: $|A|=(x-y)(y-z)(y+z)-(x-y)(x+y)(y-z)=(x-y)(y-z)(y+z-x-y)$ Step 4. We proved the expression: $|A|=(x-y)(y-z)(z-x)$
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