Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Section 10.1 - Systems of Linear Equations in Two Variables - 10.1 Exercises - Page 689: 65

Answer

Plane: 120 mi/h Wind: 30 mi/h

Work Step by Step

Speed is the ratio of distance and the time ,$v=\displaystyle \frac{d}{t}$. From $v=\displaystyle \frac{d}{t}$it follows that $d=vt\qquad (*)$ Let $v$ be the speed of the plane in still air. Let $w $ be the speed of the wind. When flying into the headwind, the speed is $ v-w$ and time spent is $t=2$ hours So, we have by (*) $180=2(v-w)$ When the plane flies in the same direction as the wind, the speed is $v+w$ The time is $t=1$h 12min=($1+\displaystyle \frac{12}{60}$) h $=1.2$ h So, we have by (*) $180=1.2(v+w)$ $\left\{\begin{array}{ll} 180=2v-2w & /\times 1.2\\ 180=1.2v+1.2w & /\times 2 \end{array}\right.$ (we are solving by elimination, eliminating w) $\left\{\begin{array}{ll} 216=2.4v-2.4w & \\ 360=2.4v+2.4w & /add \end{array}\right.$ $576=4.8v\qquad/\div 4.8$ $\displaystyle \frac{576}{4.8}=v$ $v=$120 mi/h Back-substitute: $180=2v-2w$ $180=2(120)-2w$ $180=240-2w\quad/-240$ $-60=-2w\quad/\div(-2)$ $30=w$ w= 30 mi/h
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