Answer
$(5, 10)$
Work Step by Step
Given system is-
$0.4x +1.2y$ = $14$ __ eq.1
$12x -5y$ = $10$ __ eq.2
Multiplying eq.1 by '30'-
$12x +36y$ = $420$ __ eq.3
Subtracting eq.2 from eq.3 -
$(12x +36y)-(12x -5y)$ = $420-10$
$12x +36y-12x +5y)$ = $410$
$41y)$ = $410$
i.e. $y$ = $\frac{410}{41}$
i.e. $y$ = $10$
Substituting for $y$ in eq.2
$12x -5(10)$ = $10$
i.e. $12x -50$ = $10$
i.e. $12x$ = $10+50$
i.e. $12x$ = $60$
i.e. $x$ = $\frac{60}{12}$
i.e. $x$ = $5$
Thus $(5, 10)$ is the solution of given system.
