## Precalculus: Mathematics for Calculus, 7th Edition

A) 3 terms B) $x(x+1)^{2}$ C) $-\frac{2x^2+1}{x(x+1)^{2}}$
A) Terms are those that are separated by a + or - sign. In this case there are 3 terms. B) The common denominator is $x(x+1)^{2}$ C) $$\frac{(1(x+1)^{2}-2x(x+1)-x(x))^{2}}{x(x+1)^{2}}$$ $$\frac{x^{2}+2x+1-2x^2-2x-x^{2}}{x(x+1)^{2}}$$ $$-\frac{2x^2+1}{x(x+1)^{2}}$$