## Precalculus: Mathematics for Calculus, 7th Edition

The domain is {$x|x\gt1$}
Since x is on the denominator and is under a radical sign, it must fulfill two conditions: 1) The denominator cannot be a negative number 2) The denominator cannot be zero Solve for x. $x-1=0$ $x=1$ Therefore, $x\gt1$ which fulfills the two conditions.