Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 12


The domain is {$x|x\gt1$}

Work Step by Step

Since x is on the denominator and is under a radical sign, it must fulfill two conditions: 1) The denominator cannot be a negative number 2) The denominator cannot be zero Solve for x. $x-1=0$ $x=1$ Therefore, $x\gt1$ which fulfills the two conditions.
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