## Precalculus: Mathematics for Calculus, 7th Edition

The domain is {$x|x\ne-1, x\ne2$}
Denominator cannot be $0$. Solve the denominator to find the value where $x=0$. Factor the polynomial in the denominator. $x^{2}-x-2=0$ $(x+1)(x-2)=0$ $x=-1$ and $x=2$