Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 23: 76

Answer

$a)$ $xy^{2}$ $b)$ $2x^{1/6}$

Work Step by Step

$a)$ $\sqrt[5]{x^{3}y^{2}}\sqrt[10]{x^{4}y^{16}}$ Rewrite the radical expressions as powers with rational exponent: $\sqrt[5]{x^{3}y^{2}}\sqrt[10]{x^{4}y^{16}}=(x^{3}y^{2})^{1/5}(x^{4}y^{16})^{1/10}=...$ Evaluate the powers: $...=(x^{3/5}y^{2/5})(x^{2/5}y^{8/5})=...$ Evaluate the product: $...=x^{3/5+2/5}y^{2/5+8/5}=x^{5/5}y^{10/5}=xy^{2}$ $b)$ $\dfrac{\sqrt[3]{8x^{2}}}{\sqrt{x}}$ Rewrite the radical expressions as powers with rational exponent: $\dfrac{\sqrt[3]{8x^{2}}}{\sqrt{x}}=\dfrac{(8x^{2})^{1/3}}{x^{1/2}}=...$ Evaluate the power in the numerator: $...=\dfrac{(\sqrt[3]8)x^{2/3}}{x^{1/2}}=\dfrac{2x^{2/3}}{x^{1/2}}=...$ Evaluate the division: $...=2x^{2/3-1/2}=2x^{1/6}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.