Precalculus: Mathematics for Calculus, 7th Edition

$a)$ $x\sqrt{x}$ $b)$ $x\sqrt[5]{x}$
$a)$ $\sqrt{x^{3}}$ Rewrite $x^{3}$ as $x^{2}\cdot x$ and then simplify: $\sqrt{x^{3}}=\sqrt{x^{2}\cdot x}=x\sqrt{x}$ $b)$ $\sqrt[5]{x^{6}}$ Rewrite $x^{6}$ as $x^{5}\cdot x$ and simplify: $\sqrt[5]{x^{6}}=\sqrt[5]{x^{5}\cdot x}=x\sqrt[5]{x}$