Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.2 - Exponents and Radicals - 1.2 Exercises - Page 23: 72


$a)$ $x^{2}\sqrt{x}$ $b)$ $x\sqrt[4]{x^{2}}$

Work Step by Step

$a)$ $\sqrt{x^{5}}$ Rewrite $x^{5}$ as $x^{4}\cdot x$ and evaluate: $\sqrt{x^{5}}=\sqrt{x^{4}\cdot x}=x^{2}\sqrt{x}$ $b)$ $\sqrt[4]{x^{6}}$ Rewrite $x^{6}$ as $x^{4}\cdot x^{2}$ and evaluate: $\sqrt[4]{x^{6}}=\sqrt[4]{x^{4}\cdot x^{2}}=x\sqrt[4]{x^{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.