## Precalculus: Mathematics for Calculus, 7th Edition

$a)$ $x^{2}\sqrt{x}$ $b)$ $x\sqrt[4]{x^{2}}$
$a)$ $\sqrt{x^{5}}$ Rewrite $x^{5}$ as $x^{4}\cdot x$ and evaluate: $\sqrt{x^{5}}=\sqrt{x^{4}\cdot x}=x^{2}\sqrt{x}$ $b)$ $\sqrt[4]{x^{6}}$ Rewrite $x^{6}$ as $x^{4}\cdot x^{2}$ and evaluate: $\sqrt[4]{x^{6}}=\sqrt[4]{x^{4}\cdot x^{2}}=x\sqrt[4]{x^{2}}$