Answer
a) $P=kAv^3$
b) $4P$
c) $\dfrac{3P}{8}$
Work Step by Step
a) As per the given problem, we have:
$P=kAv^3$
Here, $k$ is defined as constant of proportionality
b) From part (a), we have $P=kAv^3$
Plug the given values in the above expression, we get
$P_n=k(\dfrac{A}{2})(2v)^3=4P$
c) From part (a), we have $P=kAv^3$
Then, $P_n=k(3A)(\dfrac{v}{2})^3=\dfrac{3P}{8}$
