Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.12 - Modeling Variation - 1.12 Exercises - Page 129: 53

Answer

$\dfrac{f}{2}$

Work Step by Step

As per the given problem, we have: $f=k \dfrac{1}{L}$ Here, $k$ is defined as constant of proportionality when the length gets doubled then we have $f_n=\dfrac{k}{2L}$ Plug the given data in the above expression, we get $f_n=\dfrac{k}{L_n}=\dfrac{k}{2L}$ This gives: $f_n=\dfrac{f}{2}$
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