Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.12 - Modeling Variation - 1.12 Exercises - Page 129: 52

Answer

$x_n=20(\sqrt[3]{2})$ft

Work Step by Step

As per the given problem, we have: $H=k \dfrac{w}{x^3}$ Here, $k$ is defined as constant of proportionality when the amount of wood gets doubled then we have $k \dfrac{w}{x^3}=k \dfrac{w_n}{x_n^3}$ Plug the given data in the above expression, we get $\dfrac{w}{(20)^3}=\dfrac{2w}{x_n^3}$ This gives: $x_n=20(\sqrt[3]{2})$ft
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