Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.12 - Modeling Variation - 1.12 Exercises - Page 127: 29

Answer

$R=\dfrac{27.5}{\sqrt{x}}$

Work Step by Step

$R$ is inversely proportional to $\sqrt{x}$ so the equation that relates the variables is: $R=\dfrac{k}{\sqrt{x}}$ where k = constant of proportionality. If x = 121 , then $R = 2.5$. Substitute these values into the equation above to have: $R=\dfrac{k}{\sqrt{x}} \\2.5 = \dfrac{k}{\sqrt{121}} \\2.5= \dfrac{k}{11} \\2.5(11) = k \\27.5=k$ The constant of proportionality is $27.5$. Thus, the equation that relates R and x is: $R=\dfrac{27.5}{\sqrt{x}}$
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