Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.12 - Modeling Variation - 1.12 Exercises - Page 127: 28

Answer

$H=81l^{2}w^{2}$

Work Step by Step

$H$ is jointly proportional to $l^2$ and $w^2$ so the equation that relates the variables is: $H=k(l^2w^2wh)$ where k = constant of proportionality. If l = 2 and $w = \frac{1}[{3}$, then H = 36. Substitute these values into the equation above to have: $H=k(l^2w^2) \\36 = k(2^2 \cdot (\frac{1}{3})^2) \\36=k(4 \cdot \frac{1}{9}) \\36 = k \cdot \frac{4}{9} \\\frac{9}{4} \cdot 36 = k \\81=k$ The constant of proportionality is $81$. Thus, the equation that relates H, l, and w is: $H=81(l^2w^2)$
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