Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.11 - Solving Equations and Inequalities Graphically - 1.11 Exercises - Page 121: 23

Answer

$-1.00$, $0.00$ and $1.00$

Work Step by Step

Given equation- $x^{\frac{1}{3}} -x$ = $0$ , in the interval [-3,3] i.e $x^{\frac{1}{3}}$ = $x$ Raising both sides to power '3'- $x $ = $x^{3}$ i.e. $x^{3} - x $ = $0$ in the interval [-3,3] We are asked to find all solutions 'x' that satisfy $-3 \leq x \leq 3$, so we use a graphing calculator to graph the equation in a viewing rectangle for which the x-values are restricted to the interval [-3,3] . Graphing $y$ = $x^{3} - x $, using graphing calculator- There are three $x-intercepts$ in the given interval, $x= -1.00$, $0.00$ and $1.00$ i.e. $x= -1.00$, $0.00$ and $1.00$
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