Answer
$x= 3.00$ and $4.00$
Work Step by Step
Given equation-
$x^{2}-7x+12$ = $0$ in the interval [0,6]
We are asked to find all solutions x that satisfy $0 \leq x \leq6$, so we use a graphing calculator to graph the equation in a viewing rectangle for which the x-values are restricted to the interval [0,6] .
Graphing $y$ = $x^{2}-7x+12$, using graphing calculator-
There are two $x-intercepts$ in the given interval, $x= 3.00$ and $x= 4.00$
Thus in the given interval, $x= 3.00$ and $4.00$
