Answer
$x= 1.00, 2.00$ and $3.00$
Work Step by Step
Given equation-
$x^{3}-6x^{2}+11x-6$ = $0$ in the interval [-1,4]
We are asked to find all solutions x that satisfy $-1 \leq x \leq 4$, so we use a graphing calculator to graph the equation in a viewing rectangle for which the x-values are restricted to the interval [-1,4] .
Graphing $y$ = $x^{3}-6x^{2}+11x-6$, using graphing calculator-
There are three $x-intercepts$ in the given interval, $x= 1.00, 2.00$ and $3.00$
Thus in the given interval, $x= 1.00, 2.00$ and $3.00$
