Answer
No solution.
Work Step by Step
Given equation is-
$x^{2}+3$ = $2x$
i.e. $x^{2}-2x+3$ = $0$
Algebraic Solution:
$x^{2}-2x+3$ = $0$
Finding discriminant-
D= $b^{2} - 4ac$ = $(-2)^{2} - 4.(1).(3)$ = $4-12$ = $-8$
As discriminant is negative, there is no real solution of the equation.
i.e. Equation has no solution
Graphical Solution:
$x^{2}-2x+3$ = $0$
Now graphing $y$ = $x^{2}-2x+3$
We get no $x-intercept$
i.e. Equation has no real solution.
