Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises - Page 10: 5


$\mid$ b-a $\mid$ ; 7

Work Step by Step

The Distance between points on a real line uses the formula: d(a,b) = $\mid$ b-a $\mid$ Now we are given the question to solve the distance between -5 and 2. We plugin -5 as a and 2 as b. d(-5,2) = $\mid$ 2-(-5) $\mid$ Then, we distribute the minus sign to the -5. Since a negative times a negative is a positive, a will become a positive 5. d(-5,2) = $\mid$ 2+5 $\mid$ Add the two numbers. d(-5,2) = $\mid$ 7 $\mid$ The absolute of the number 7 will still be a positive 7. d(-5,2) = 7
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.