Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.1 - Real Numbers - 1.1 Exercises - Page 10: 38


a.) True b.) True

Work Step by Step

a.) $\frac{7}{11}$ $\geq$ $\frac{8}{13}$ The Least Common Denominator of 11 and 13 = 143 (They are both prime numbers and only share multiples of each other) $\frac{91}{143}$ $\geq$ $\frac{88}{143}$ In terms of the same denominator, 91 is bigger than 88. True b.)-$\frac{3}{5}$ $\gt$ -$\frac{3}{4}$ The Least Common Denominator of 5 and 4 = 20 -$\frac{12}{20}$ $\gt$ -$\frac{15}{20}$ Since both numbers are negative, the number that is closer to 0 [-$\frac{12}{20}$]are bigger than the one that is farther away [-$\frac{15}{20}$] True
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.