Answer
(a) $x\gt0$
(b) $t\lt4$
(c) $a\geq\pi$
(d) $-5\lt x \lt\frac{1}{3}$
(e) $|p-3|\leq5$
Work Step by Step
(a) $x$ is positive whenever it is greater than $0$.
$x>0$
(b) $t$ is less than 4, meaning we need a "less than" sign
$t<4$
(c) $a\geq \pi$
(d) $-5\lt x \lt\frac{1}{3}$
(e) $|p-3|\leq 5 $