Answer
$y=\dfrac{1}{2}x+\dfrac{5}{2}$
Work Step by Step
The equation of a line in the point-slope form is the following:
$y-y_1=m(x-x_1)$, where $m$ is the slope and the point $(x_1,y_1)$ is on the graph.
Here, our line's slope can be calculated by the formula:
$m=\dfrac{y_2-y_1}{x_2-x_1}$, where the points $(x_1,y_1)$ and $(x_2,y_2)$ are on the line.
We can plug in the given two points:
$m=\dfrac{2-3}{-1-1}=\dfrac{-1}{-2}=\dfrac{1}{2}$
Using the point $(1, 3)$ and the slope $\frac{1}{02}$, the equation can be written as:
$y-3=\dfrac{1}{2}(x-1)\\
y-3=\dfrac{1}{2}x-\dfrac{1}{2}\\
y=\dfrac{1}{2}x-\dfrac{1}{2}+3\\
y=\dfrac{1}{2}x+\dfrac{5}{2}$
