Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.3 Lines - F.3 Assess Your Understanding - Page 30: 47



Work Step by Step

The equation of a line in the point-slope form is the following: $y-y_1=m(x-x_1)$, where $m$ is the slope and the point $(x_1,y_1)$ is on the graph. Here, our line's slope is: $m=-\frac{2}{3}$ Therefore, using the point $(4, -3)$ and the slope $-\frac{2}{3}$, the equation can be written as: $y-(-1)=-\dfrac{2}{3}(x-1)$ $y+1=-\dfrac{2}{3}(x-1)\\ y+1=-\dfrac{2}{3}x+\dfrac{2}{3}\\ y=-\dfrac{2}{3}x+\dfrac{2}{3}-1\\ y=-\dfrac{2}{3}x-\dfrac{1}{3} $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.