## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Thus, $x=0$ is the only x-intercept. Thus, $y=0$ is the only y-intercept. Origin symmetry.
To find the x-intercept of an equation, we set $y=0$ and solve: $y=\sqrt[3]{x}$ $0=\sqrt[3]{x}$ $x=0^3=0$ Thus, $x=0$ is the only x-intercept. Similarly, to find the y-intercept of an equation, we set $x=0$ and solve: $y=\sqrt[3]{x}$ $y=\sqrt[3]{0}=0$ Thus, $y=0$ is the only y-intercept. To check for symmetry about the x-axis, we replace every instance of $y$ with $-y$ in the original equation. The new equation must be equivalent to the original. We have: $-y= \sqrt[3]{x}$ which is not the same as $y= \sqrt[3]{x}$ Thus, there is no symmetry about the x-axis. For symmetry about the y-axis, replace every instance of $x$ with $-x$. We have $y = \sqrt[3]{-x}=-\sqrt[3]{x}$ which is not the same as $y = \sqrt[3]{x}$ Thus, there is no symmetry about the y-axis. However, the graph is symmetric with respect to the origin since if we replace $x,y$ by $-x,-y$, we get the same equation: $-y= \sqrt[3]{-x}= -\sqrt[3]{x}$ Thus $y= \sqrt[3]{x}$. which is the same as the original equation. Thus, we have origin symmetry.