## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

There are two $x$-intercepts: $-2$ and $2$. The y-intercept is $4$. See the graph below.
In order to find the $x$-intercept, we have to plug $y=0$ into the equation, and the $x$-coordinate will give us the intercept itself. $y=-x^2+4$ $0=-x^2+4$ $x^2=4$ $x=\pm2$ The same thing should be done for the $y$-intercept, however, here $x=0$ should be plugged into the equation. $y=-x^2+4$ $y=-0^2+4$ $y=4$ There are two $x$-intercepts: $-2$ and $2$. The $y$-intercept is $4$ Few other points that will help us plot the graph: If $x=1$ $y=-1^2+4=3$ The point $(1,3)$ is on the graph. If $x=-1$ $y=-(-1)^2+4=3$ The point $(-1,3)$ is on the graph. If $x=3$ $y=-3^2+4=-5$ The point $(3,-5)$ is on the graph.