There are two x-intercepts: $-1$ and $1$ . The y-intercept is $-1$ . See the graph below.
Work Step by Step
In order to find the $x$-intercept, we have to plug $y=0$ into the equation, and the $x$-coordinate will give us the intercept itself. $y=x^2-1$ $0=x^2-1$ $x^2=1$ $x=\pm1$ The same thing should be done for the $y$-intercept, however, here $x=0$ should be plugged into the equation. $y=x^2-1$ $y=0^2-1$ $y=-1$ There are two $x$-intercepts: $-1$ and $1$. The $y$-intercept is $-1$ Few other points that will help us plot the graph: If $x=0$ $y=0^2-1=-1$ The point $(0,-1)$ is on the graph. If $x=-2$ $y=(-2)^2-1=3$ The point $(-2,3)$ is on the graph. If $x=2$ $y=2^2-1=3$ The point $(2,3)$ is on the graph.