Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter F - Foundations: A Prelude to Functions - Section F.2 Graphs of Equations in Two Variables; Intercepts; Symmetry - F.2 Assess Your Understanding - Page 16: 15

Answer

The $x$-intercept is $-2$ The $y$-intercept is $2$ See the graph below.

Work Step by Step

In order to find the $x$-intercept, we have to plug $y=0$ into the equation, and the $x$-coordinate will give us the intercept itself. $y=x+2$ $0=x+2$ $x=-2$ The same thing should be done for the $y$-intercept, however, here $x=0$ should be plugged into the equation. $y=x+2$ $y=0+2$ $y=2$ The $x$-intercept is $-2$ The $y$-intercept is $2$. Few other points that will help us plot the graph: If $x=-1$ $y=-1+2=1$ The point $(-1,1)$ is on the graph. If $x=1$ $y=1+2=3$ The point $(1,3)$ is on the graph. If $x=2$ $y=2+2=4$ The point $(2,4)$ is on the graph.
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