Answer
$x=2cos(\frac{2\pi}{3}t), y=3sin(\frac{2\pi}{3}t)$ with $0\le t\le3$
Work Step by Step
Answer may vary.
1. Based on the given conditions, we can write $x=2cos(kt), y=3sin(kt)$ with $0\le t\le3$
2. With $p=3$, we have $\frac{2\pi}{k}=3$ and $k=\frac{2\pi}{3}$
3. Thus $x=2cos(\frac{2\pi}{3}t), y=3sin(\frac{2\pi}{3}t)$ with $0\le t\le3$