Answer
$x=2cos(\pi t), y=-3sin(\pi t)$ with $0\le t\le2$
Work Step by Step
Answer may vary.
1. Based on the given conditions, we can write $x=2cos(kt), y=-3sin(kt)$ with $0\le t\le2$
2. With $p=2$, we have $\frac{2\pi}{k}=2$ and $k=\pi$
3. Thus $x=2cos(\pi t), y=-3sin(\pi t)$ with $0\le t\le2$