Answer
$x=2sin(2\pi t), y=3cos(2\pi t)$ with $0\le t\le1$
Work Step by Step
Answer may vary.
1. Based on the given conditions, we can write $x=2sin(kt), y=3cos(kt)$ with $0\le t\le1$
2. With $p=1$, we have $\frac{2\pi}{k}=1$ and $k=2\pi$
3. Thus $x=2sin(2\pi t), y=3cos(2\pi t)$ with $0\le t\le1$