Answer
$(x-2)^2+(y+3)^2=1$
Work Step by Step
Given center $(2,-3)$ and radius 1, we have the circle equation $(x-2)^2+(y+3)^2=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 676: 6
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