Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 676: 3

$(\pm2,0),(0,\pm4)$

1. To find the x-intercept(s), let $y=0$, we have $16-4x^2=0$, thus $x=\pm2$ or $(\pm2,0)$ 2. To find the y-intercept(s), let $x=0$, we have $y^2=16$, thus $y=\pm4$ or $(0,\pm4)$ 3. We have intercepts $(\pm2,0),(0,\pm4)$