Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Section 9.3 The Ellipse - 9.3 Assess Your Understanding - Page 676: 2

Answer

$\frac{9}{4}$

Work Step by Step

Form a perfect square: $x^2-3x+(\frac{3}{2})^2=(x-\frac{3}{2})^2$, thus we add $(\frac{3}{2})^2=\frac{9}{4}$
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