Answer
$r=8sin\theta$
See graph.
Work Step by Step
1. Withe the center and radius, we can write the circle as $x^2+(y-4)^2=16$ or $x^2+y^2-8y=0$
2. We have $r^2-8r\ sin\theta=0$ or $r=8sin\theta$
3. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Cumulative Review - Page 721: 9
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