Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Cumulative Review - Page 721: 12

Answer

$y=\frac{1}{5}x^2+5$

Work Step by Step

Use the relation $sec^2t=tan^2t+1$, we have $\frac{y}{5}=(\frac{x}{5})^2+1$ or $y=\frac{1}{5}x^2+5$
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