Answer
$22.5^\circ$
Work Step by Step
From $cot(2\theta)=1$, we have $2\theta=k\pi+\frac{\pi}{4}$, thus $\theta=\frac{k\pi}{2}+\frac{\pi}{8}$ which gives $\theta=\frac{\pi}{8}=22.5^\circ$ within the region.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 9 - Analytic Geometry - Cumulative Review - Page 721: 11
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