Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 9 - Analytic Geometry - Cumulative Review - Page 721: 8

Answer

$\theta=\frac{\pi}{6}$

Work Step by Step

1. Given the line passing $(0,0)$ and slope $m=tan30^\circ=\frac{\sqrt 3}{3}$, thus we have $y=\frac{\sqrt 3}{3}x$ in rectangular coordinates. 2. We have $r\ sin\theta=\frac{\sqrt 3}{3}r\ cos\theta$ or $tan\theta=\frac{\sqrt 3}{3}$ or $\theta=\frac{\pi}{6}$
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