Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 645: 7

Answer

All the points are in the form of $(x,0,z)$, which is the $xz$-plane.

Work Step by Step

Since $y$ is equal to $0$, then the given plane is the $xz-$plane in which all the points are in the form of $(x,0,z)$, where $x,z$ are any real numbers.
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