Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.6 Vectors in Space - 8.6 Assess Your Understanding - Page 645: 26

Answer

$(-6,-3,0),(-2,7,0),(-6,7,0),(-2,-3,1),(-2,7,1),(-6,-3,1)$.

Work Step by Step

1. Given vertices $(-2,-3,0),(-6,7,1)$, we can find other vertices: X-Y plane (z=0): $(-6,-3,0),(-2,7,0),(-6,7,0),$ Y-Z plane (x=-2): $(-2,7,0),(-2,-3,1),(-2,7,1),$ X-Z plane (y=-3): $(-6,-3,0),(-2,-3,1),(-6,-3,1),$ 2. Remove repeating points to get $(-6,-3,0),(-2,7,0),(-6,7,0),(-2,-3,1),(-2,7,1),(-6,-3,1)$.
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