Answer
All the points are in the form of $(x,3,z)$; where $x,z$ are any real numbers.
Work Step by Step
Since $y$ is set to $3$, the given plane is parallel to the $xz-$ plane and is $3$ units to the right of it. Thus, all the points are in the form of $(x,3,z)$, where $x,z$ are any real numbers.