Answer
$F=20\sqrt3i+20j$
Work Step by Step
Let us consider the vector $v=pi+qj$. The unit vector $u$ in the same direction as $v$ is given by: $u=\dfrac{v}{||v||}$
and the magnitude of any vector (let us say $v$) can be determined using the formula
$||v||=\sqrt{p^2+q^2} $
We have: $F_i=||v|| \cos\alpha=(40) \cos30^\circ=20\sqrt3$, and
$F_j=||v|| \sin \alpha=40 \sin30^\circ=20$
Therefore, the components of the force vector are: $F=20\sqrt3i+20j$
