Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 627: 69

Answer

$258.69^{\circ}$

Work Step by Step

Let us consider that a vector $v$ is given by $v=pi+qj$ and makes an angle of $\alpha$ with the positive $x$-axis. The direction angle $\alpha$ for the given vector can be determined using the formula: $\tan \alpha=\dfrac{q}{p}$ Here, we have: $v=-i - 5j $ Now, $\tan \alpha=\dfrac{ -5}{-1}=5$ Since the angle must be in the quadrant III, the direction angle is: $\alpha=\arctan (5) \approx 78.69^{\circ}+180^{\circ}=258.69^{\circ}$
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