## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\dfrac{3}{5}i-\dfrac{4}{5}j$
Solve for $||v||$ sing the formula $||v||=\sqrt{a_1^2+b_1^2}$ to obtain: $||\textbf{v}||$= $\sqrt {3^{2}+4^{2}}= \sqrt {25}$=5 Thus, the unit vector in the same direction as $\textbf{v}$ is: $u= \dfrac{v}{|\textbf{v}|}$= $\dfrac{1}{5}(3i-4j)$ = $\dfrac{3}{5}i-\dfrac{4}{5}j$.