Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 626: 33


$ -i +j$ and the position vector is: $(-1, 1)$

Work Step by Step

If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then $v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$ Here, we have: $A=(1, 0)$ and $B=(0, 1)$ Therefore, $v=(0-1)i+(1-0) \ j = -i +j$ and the position vector is: $(-1, 1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.