## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$-i +j$ and the position vector is: $(-1, 1)$
If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then $v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$ Here, we have: $A=(1, 0)$ and $B=(0, 1)$ Therefore, $v=(0-1)i+(1-0) \ j = -i +j$ and the position vector is: $(-1, 1)$