Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 626: 26

Answer

$8$

Work Step by Step

Let us consider that a vector $v$ is given by: $v=pi+qj+rz$ The magnitude of a vector can be determined using the formula $||v||=\sqrt{p^2+q^2+r^2} $ Here, we have: $||-4 v||=|-4| ||v|| =(4)(2)=8$
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